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3x^2=7x-1
We move all terms to the left:
3x^2-(7x-1)=0
We get rid of parentheses
3x^2-7x+1=0
a = 3; b = -7; c = +1;
Δ = b2-4ac
Δ = -72-4·3·1
Δ = 37
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{37}}{2*3}=\frac{7-\sqrt{37}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{37}}{2*3}=\frac{7+\sqrt{37}}{6} $
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